Chapter 7: Square Functions, the Heat Flow, and Paraproducts
This chapter has two aims: to recover an \(L^p\) norm from its frequency pieces, and to organize the interactions of these pieces in a nonlinear equation. The first is the square function theorem, proved from Khintchine's inequality, the Calderón–Zygmund theorem, and duality. The heat equation then illustrates the linear theory, and products lead to the paraproduct decomposition.
§ 01Setting and what we keep from Chapter 5
We work on \(\mathbb R^d\), \(d\ge1\), with the Fourier convention of Chapter 5:
The dyadic cutoffs are those of Chapter 5: \(\varphi\) is a radial, radially nonincreasing bump with \(\varphi=1\) on \(\{|\xi|\le1\}\) and \(\varphi=0\) on \(\{|\xi|\ge2\}\), and
Thus \(\psi\ge0\), \(\operatorname{supp}\psi\subset\{1/2\le|\xi|\le2\}\), \(\sum_{k\in\mathbb Z}\psi(2^{-k}\xi)=1\) for \(\xi\ne0\), and \(\sum_{k\le j}\psi(2^{-k}\xi)=\varphi(2^{-j}\xi)\) for \(\xi\ne0\). In this chapter we write the kernel as
(Chapter 5 called this kernel \(K\); we reserve \(K\) for Calderón–Zygmund kernels.) \(\Phi\) is Schwartz and \(\int\Phi=\psi(0)=0\): each \(P_k\) measures variation at scale \(2^{-k}\) and removes a constant background. \(P_kf\) is localized in frequency, not in space; its kernel is concentrated at distances of order \(2^{-k}\) with rapidly decaying tails.
We use from Chapter 5, without repeating the proofs: \(L^2\) reconstruction and almost orthogonality \(\|f\|_2^2\simeq\sum_k\|P_kf\|_2^2\) (§3); Bernstein's inequality \(\|P_kf\|_r\lesssim2^{kd(1/p-1/r)}\|P_kf\|_p\) for \(p\le r\) (§5); the dyadic descriptions of \(H^s\), \(\dot H^s\) and the Besov norms (§6–7); and the critical embedding and its failure (§8–10). Constants in \(\lesssim\) may depend on \(d\), the exponents, and the fixed cutoff, but not on the function or the dyadic index.
Remark. Homogeneous reconstruction and the general critical embedding
Annular cutoffs annihilate polynomials, so a homogeneous Besov seminorm cannot distinguish \(f\) from \(f\) plus a polynomial. Whenever an actual function is reconstructed, we choose the representative with vanishing low-frequency remainder:
Schwartz functions satisfy this convention. With it, the argument of Proposition 5.6 extends from \(p=2\) to every \(1\le p\le\infty\): Bernstein with \(r=\infty\) gives
and the finite right side makes the reconstruction converge uniformly. So \(\dot B^{d/p}_{p,1}\hookrightarrow L^\infty\), and likewise \(B^{d/p}_{p,1}\hookrightarrow L^\infty\), using \(\|P_{\le0}f\|_\infty\lesssim\|P_{\le0}f\|_p\) for the low block. The failure of \(H^{d/2}\hookrightarrow L^\infty\) can also be seen with equal weights: for a real Schwartz \(h\) with Fourier support in \(\{1<|\xi|<2\}\) and \(h(0)>0\), the functions \(f_N=N^{-1/2}\sum_{j=1}^Nh(2^{3j}x)\) have disjoint Fourier supports above unit frequency, so \(\|f_N\|_{H^{d/2}}\lesssim1\), while \(f_N(0)=\sqrt N\,h(0)\). Quadratic summability lets the bands pile up at one point; the \(\ell^1\) sum in \(\dot B^{d/2}_{2,1}\) controls precisely this accumulation.
§ 02Why a nonlinear equation requires frequency analysis
Consider the wave or Klein–Gordon equation
with \(m\ge0\). The motivating nonlinearity is \(N(u)=\lambda u^3\); the sign of \(\lambda\) does not matter for the norm calculation below. On a time interval \(I\),
This explains the norm \(L_t^3L_x^6\): it makes the cubic forcing integrable in time in the energy estimate. As in Chapter 4, for a global energy solution, finiteness of this norm on \([0,\infty)\) is a sufficient scattering criterion.
Here scattering means approaching a solution of the linear equation in the energy norm
For \(m>0\) this is equivalent to the \(H^1\times L^2\) norm; for \(m=0\) it is the homogeneous energy norm. Let \(U_m(t)\) be the linear energy evolution, an isometry group on \(\mathcal E_m\), and \(X(t)=(u(t),\partial_tu(t))\). Duhamel's formula \(X(t)=U_m(t)X(0)+\int_0^tU_m(t-s)(0,N(u(s)))\,ds\) can be rewritten as
Since \(\|U_m(-s)(0,F)\|_{\mathcal E_m}=\|F\|_2\), the integral converges absolutely in \(\mathcal E_m\) as \(t\to\infty\) when \(N(u)\in L_t^1L_x^2([0,\infty)\times\mathbb R^d)\). Its limit defines \(X_+=X(0)+\int_0^\infty U_m(-s)(0,N(u(s)))\,ds\), and applying the isometry \(U_m(t)\),
This is a criterion for a solution already known to exist globally. It is neither a proof of global existence nor a claim that every scattering solution satisfies this particular spacetime bound.
Concentration and transfer to fine scales. The density \(|u(t,x)|^6\) might concentrate near a point. A precise model is
with \(w\) Schwartz. A change of variables gives \(\|u_k\|_6=1\), and for every bounded continuous \(a\), \(\int a(x)|u_k(x)|^6\,dx=\int a(x_0+2^{-k}y)|w(y)|^6\,dy\to a(x_0)\); that is,
The spatial width is \(2^{-k}\) and the Fourier profile is dilated by \(2^k\): if \(\widehat w\) lives in a unit annulus, \(u_k\) is localized at \(|\xi|\sim2^k\). (A one-dimensional picture is the family \(2^ke^{-2^{2k}(x-x_0)^2}\), \(k=0,1,2,\dots\), all with integral \(\sqrt\pi\).) Concentration of the density alone does not force its integral, or the \(L^6\) norm, to diverge. What matters for the \(L_t^3L_x^6\) norm is how long the concentration persists in time.
Applying \(P_k\) to the equation leaves the linear terms diagonal in frequency, but the cubic term becomes
It is not \((P_ku)^3\): a nonlinear term couples different scales. One may picture a transfer to successively finer scales during the evolution,
Remark. The arrows are schematic
Establishing such a transfer requires analysis of the solution; it is a possible mechanism, not a proved evolution law. One interaction cannot jump far: if \(\widehat u\) is supported in \(\{|\xi|\le R\}\), then \(\widehat{u^3}\) is supported in \(\{|\xi|\le3R\}\) (see §11). An arbitrarily large jump requires further evolution and repeated interactions.
Two tools are therefore needed: the square function, to reconstruct an \(L^p\) norm from the bands, and paraproducts, to organize the nonlinear interactions.
§ 03The Littlewood–Paley square function
定义 3.1Square function
The Littlewood–Paley square function of \(f\) is
For \(f\in L^2\), Tonelli and almost orthogonality give \(\int(Sf)^2=\sum_k\|P_kf\|_2^2\le\|f\|_2^2<\infty\), so \(Sf\) is finite almost everywhere.
定理 3.2Square function theorem
For \(1<p<\infty\) there are constants \(0<c_p\le C_p<\infty\) such that
The estimate holds first for Schwartz functions, hence for \(C_c^\infty\), and extends to every \(f\in L^p\) by density.
The proof occupies §5–8. For the density step: the upper bound for Schwartz functions shows that \(f\mapsto(P_kf)_k\) extends to a bounded map \(L^p\to L^p(\ell^2)\), and the lower bound then passes to limits.
At a point \(x\), \(Sf(x)\) records the quadratic size of the oscillations seen at every scale. Adding the bands to reconstruct \(f(x)\) retains their relative signs and phases; the square function discards cancellation between different bands. The theorem says that after spatial integration in \(L^p\) these two measurements are comparable. It does not assert a pointwise comparison.
For \(p=2\), Tonelli and Plancherel give
For \(p\ne2\), the square sum must remain inside the spatial \(L^p\) norm; it cannot simply be replaced by \(\big(\sum_k\|P_kf\|_p^2\big)^{1/2}\).
The cancellation example. On \(\mathbb R\) take
For our cutoff, \(\psi(1)=\varphi(1)-\varphi(2)=1\), while \(\psi(1/2)=\varphi(1/2)-\varphi(1)=0\) and \(\psi(2)=\varphi(2)-\varphi(4)=0\). Since \(\widehat f\) is supported at \(\pm1,\pm2\) and \(\psi\) is even,
Consequently \(f(0)=0\) while \(Sf(0)=\sqrt2\). This correctly demonstrates the loss of pointwise cancellation.
Remark. What the example does and does not show
By itself the example does not disprove an \(L^\infty\) norm estimate, which compares suprema over all \(x\). The trigonometric example may be read periodically, or as a bounded tempered distribution on \(\mathbb R\) (with \(P_k\) acting by the multiplier on its Fourier measure); it is not in \(L^p(\mathbb R)\) for finite \(p\). The norm equivalence really does fail at \(p=1\) and \(p=\infty\), but this requires separate examples, given next.
§ 04The endpoints p = 1 and p = ∞
Failure at \(p=1\). Take \(f\in C_c^\infty\), \(f\ge0\), with \(\int f=1\). Since \(\psi\ge0\) is not identically zero,
By continuity choose \(a,c>0\) with \(\Phi(z)\ge c\) for \(|z|\le3a\) (in particular \(\Phi\) is real there; in fact \(\Phi\) is real and even since \(\psi\) is). Suppose \(\operatorname{supp}f\subset\{|y|\le\rho\}\). For \(|x|\) large, choose \(k=k(x)\in\mathbb Z\) with
If \(y\in\operatorname{supp}f\), then \(|2^k(x-y)|\le2^k|x|+2^k\rho<2a+2a\rho/|x|\le3a\) once \(|x|\ge2\rho\). Hence
Thus \(Sf(x)\ge|P_{k(x)}f(x)|\gtrsim|x|^{-d}\) for large \(|x|\), so \(Sf\notin L^1\), although \(f\in L^1\). The upper estimate fails at \(p=1\).
Failure at \(p=\infty\). Choose a real Schwartz function \(h\) with \(\operatorname{supp}\widehat h\subset\{|\xi|<1/10\}\) and \(h(0)>0\), and let
Then \(\|f_N\|_\infty\ge f_N(0)=N\,h(0)\). The \(j\)th term has Fourier support within distance \(1/10\) of \(\pm2^{4j}e_1\), so its frequencies satisfy \(2^{4j}-1/10<|\xi|<2^{4j}+1/10\). The annulus \(\{2^{k-1}\le|\xi|\le2^{k+1}\}\) meets this set only for \(k\in\{4j-1,4j,4j+1\}\); these groups are disjoint for different \(j\). Therefore, at each point, at most \(3N\) bands are nonzero, each band \(P_kf_N=P_k\big(h\cos(2^{4j}x_1)\big)\) comes from a single term, and
since \(\|P_k\|_{L^\infty\to L^\infty}\le\|\Phi_k\|_1=\|\Phi\|_1\). It follows that
No constant can make \(\|f\|_\infty\lesssim\|Sf\|_\infty\) hold for all such \(f\), since the ratio is at least a multiple of \(\sqrt N\). This suffices to rule out the endpoint norm equivalence. The point is that \(\ell^2\) summation of \(N\) unit amplitudes gives \(\sqrt N\), while coherent addition gives \(N\).
§ 05Khintchine's inequality
The proof of Theorem 7.2 has three ingredients: Khintchine's inequality, the Calderón–Zygmund theorem, and duality. The first converts a family of linear operators into the square function.
Let \(\varepsilon_k\) be independent random signs, each equal to \(1\) or \(-1\) with probability \(1/2\), and write \(\mathbb E_\varepsilon\) for the expectation.
引理 5.1Khintchine's inequality
For \(0<p<\infty\) there are constants \(0<A_p\le B_p<\infty\) such that, for every finite complex sequence \((z_k)\),
The constants do not depend on the number of terms.
Equivalently, the expectation without its \(p\)th root is comparable to \(\big(\sum_k|z_k|^2\big)^{p/2}\). For \(p=2\) this is an identity: since \(\mathbb E\varepsilon_k\varepsilon_j=\delta_{kj}\) by independence, the cross terms vanish and
Random signs remove systematic alignment between different bands; the typical size of a randomly signed sum is governed by the quadratic size of its coefficients. Only \(1<p<\infty\) is needed below. A proof is the exercise at the end of the chapter.
§ 06The Calderón–Zygmund theorem used here
We use the following convolution form of the theorem, quoted without proof.
定理 6.1Calderón–Zygmund, convolution form
Let \(T\) be a linear operator bounded on \(L^2(\mathbb R^d)\) with \(\|T\|_{L^2\to L^2}\le B\). Suppose that for compactly supported smooth \(f\) and \(x\notin\operatorname{supp}f\),
where \(K\) is \(C^1\) away from the origin and
Then, for \(1<p<\infty\),
The representation is required only away from the support because a singular kernel need not define an absolutely convergent integral on the diagonal. The operator is already defined on \(L^2\); its \(L^2\) boundedness is an essential hypothesis, not a consequence of the size bound alone.
The first kernel estimate gives the strength of the interaction across a separation \(|z|\). The derivative estimate says that moving the observation point by a small fraction of that separation changes the kernel only by a controlled amount. These scale-consistent estimates let cancellation, first available in \(L^2\), control the other \(L^p\) norms. What matters for us is that the conclusion depends only on \(A\) and \(B\).
§ 07Randomized operators and the upper estimate
Work first with a finite set \(F\subset\mathbb Z\) and a fixed choice of signs \(\varepsilon=(\varepsilon_k)\). Define
命题 7.1Uniform bounds for randomized operators
For \(1<p<\infty\),
with \(C_p\) independent of both the signs and \(F\).
Proof
Since \(F\) is finite, \(K_{\varepsilon,F}\) is a Schwartz function and the integral representation of Theorem 7.4 holds trivially. The whole point is to verify the hypotheses with constants \(A,B\) independent of \(\varepsilon\) and \(F\).
The \(L^2\) bound. The multiplier is
Because \(\psi\ge0\) and the full sum is one for \(\xi\ne0\),
Plancherel gives \(\|T_{\varepsilon,F}\|_{L^2\to L^2}\le1\), so \(B=1\).
Kernel size and smoothness. The change of variables \(\eta=2^k\xi\) gives
The last integrand is supported in \(2^{k-1}\le|\eta|\le2^{k+1}\), a set of volume \(\simeq2^{kd}\). Taking absolute values shows only that \(|\Phi(2^kx)|\lesssim1\), i.e. \(|2^{kd}\Phi(2^kx)|\lesssim2^{kd}\), which cannot be summed over all \(k\). To sum the kernels we also need their rapid decay. Since \(\psi\in C_c^\infty\), repeated integration by parts gives, for \(a=0,1\) and every \(N\),
Since \(\nabla^a[2^{kd}\Phi(2^kx)]=2^{k(d+a)}(\nabla^a\Phi)(2^kx)\) and \(|\varepsilon_k|=1\), enlarging \(F\) to \(\mathbb Z\) gives
Fix \(x\ne0\), write \(r=|x|\), and choose \(j\in\mathbb Z\) with
For the low indices, bound \((1+2^kr)^{-N}\le1\) and sum the geometric series:
For the high indices, bound \((1+2^kr)^{-N}\le(2^kr)^{-N}\) and take \(N>d+a\):
since \(2^{j+1}r>1\) and \(d+a-N<0\). Thus
uniformly in \(\varepsilon\) and \(F\). The case \(a=1\) is the derivative bound. Theorem 7.4 with these uniform \(A\) and \(B=1\) proves the proposition.
Remark. Why the sum must be split
The scale with \(2^k\sim|x|^{-1}\) determines the size of the sum. Larger spatial kernels (smaller \(k\)) contribute a convergent geometric series through their amplitude; smaller spatial kernels (larger \(k\)) contribute through their rapid decay. Bounding each summand separately by \(|x|^{-d}\) and then summing over infinitely many \(k\) would miss this mechanism and would not prove the estimate.
命题 7.2The upper square-function estimate
For \(1<p<\infty\) and \(f\in\mathcal S(\mathbb R^d)\), \(\|Sf\|_p\le C_p\|f\|_p\).
Proof
Apply Khintchine pointwise with \(z_k=P_kf(x)\), \(k\in F\). Since \(\mathbb E_\varepsilon\) is a finite average over the \(2^{|F|}\) sign choices, it commutes with the integral (Tonelli), and Proposition 7.5 applies to each choice:
Let \(F=\{-M,\dots,M\}\) and send \(M\to\infty\). The left side increases to \(\|Sf\|_p^p\) by monotone convergence, and the right side does not depend on \(M\).
Working with finite sums makes the probabilistic calculation and the limiting step unambiguous.
§ 08The reverse estimate by duality
Let \(p'=p/(p-1)\) and take \(f,g\in\mathcal S(\mathbb R^d)\). With the complex pairing \(\langle f,g\rangle=\int f\overline g\),
Indeed, \(\langle f,g\rangle=\lim_M\big\langle\sum_{|k|\le M}P_kf,\sum_{|j|\le M}P_jg\big\rangle\) by \(L^2\) reconstruction, and by Plancherel \(\langle P_kf,P_jg\rangle=(2\pi)^{-d}\int\psi_k\psi_j\widehat f\,\overline{\widehat g}=0\) when \(|k-j|\ge2\), because separated annuli have disjoint supports. Absolute convergence of the remaining sum is justified by the bound below.
For each shift \(\ell\in\{-1,0,1\}\), Cauchy–Schwarz in \(k\) gives the pointwise bound
Summing over the three shifts, then applying Hölder and the upper estimate at the exponent \(p'\in(1,\infty)\),
Taking the supremum over Schwartz \(g\) with \(\|g\|_{p'}\le1\) (which are dense in the unit ball of \(L^{p'}\), as \(p'<\infty\)) gives
which completes the proof of Theorem 7.2 with \(c_p=(3C_{p'})^{-1}\).
Remark. Two or three neighbors
The lecture notes sum over \(|k-j|\le2\), i.e. five shifts, obtaining the constant \(5\). This is harmless but slightly wasteful: for the cutoffs of Chapter 5, \(\psi_k\psi_j=0\) already when \(|k-j|\ge2\), so three shifts suffice. With a different cutoff whose bands overlap more, one simply includes more shifts.
In this argument, only neighboring frequency bands can detect one another in a pairing. Duality turns this restricted overlap into control of the whole function by its quadratic band sizes.
§ 09The heat equation, scale by scale
Consider
with \(u_0\in\mathcal S(\mathbb R^d)\) to begin with. Since \(P_k\) commutes with \(\Delta\),
and the exact Fourier evolution is
Remark. A band is not an eigenfunction
The mnemonic \(\partial_tP_ku\approx-2^{2k}P_ku\) correctly identifies the decay scale, but it is not an equality: a dyadic annulus contains many values of \(|\xi|^2\), from \(2^{2k-2}\) to \(2^{2k+2}\). In particular, one cannot write \(P_ku(t,x)=e^{-t2^{2k}}P_ku_0(x)\) pointwise. Exponential decay of a band is a norm estimate.
Exponential decay of a band. For \(p=2\), the exact formula and \(|\xi|\ge2^{k-1}\) on the support give directly
命题 9.1Band decay in Lᵖ
There are constants \(C,c>0\), independent of \(k\) and \(t\ge0\), such that for \(1\le p\le\infty\)
Proof
Choose an annular cutoff \(\widetilde\psi\in C_c^\infty(\{1/4<|\eta|<4\})\) equal to one on \(\operatorname{supp}\psi\). Since \(\widetilde\psi\psi=\psi\), the operator taking \(P_ku_0\) to \(P_ku(t)\) may be taken to have multiplier
After the scaling \(\xi=2^k\eta\), its kernel is \(2^{kd}\kappa_\tau(2^kx)\), where
and it has the same \(L^1\) norm as \(\kappa_\tau\). On the fixed annular support, \(|\eta|^2\ge1/16\), and every derivative of \(m_\tau\) of fixed order is bounded by a polynomial in \(\tau\) times \(e^{-\tau/16}\). Integration by parts gives \(x^\alpha\kappa_\tau=\mathcal F^{-1}\big[(i\partial_\eta)^\alpha m_\tau\big]\), so for \(|\alpha|\le d+1\)
hence \(|\kappa_\tau(x)|\lesssim(1+|x|)^{-d-1}(1+\tau)^{d+1}e^{-\tau/16}\) and
for any fixed \(c<1/16\). Young's inequality gives the claim.
Thus a structure of size \(\ell=2^{-k}\) diffuses on the time scale \(t\sim\ell^2=2^{-2k}\): fine structures are erased first. The linear heat equation damps each frequency without transferring it to another frequency.
Recovering the \(L^p\) estimate with the square function. For \(t>0\) write
Because convolutions commute, \(P_ku(t)=G_t*P_ku_0\). Minkowski's integral inequality in \(\ell^2\) (the \(\ell^2\) norm of an integral is at most the integral of the \(\ell^2\) norms, using \(G_t\ge0\)) yields the pointwise comparison
For \(1<p<\infty\), the square function theorem and Young's inequality now give
The pointwise bound is by a spatial average of \(Su_0\), not by \(Su_0(x)\) itself: heat can arrive at a point from its neighbors.
Remark. The endpoints belong to the square function, not to the heat flow
The restriction \(1<p<\infty\) in the last chain comes from the square function theorem. The heat estimate itself is stronger and includes both endpoints:
directly from \(u(t)=G_t*u_0\) and \(\|G_t\|_1=1\). The failure at \(p=1,\infty\) in §4 concerns the square-function norm equivalence, not heat-flow contraction. The square-function route is instructive because it generalizes to evolutions without a positive kernel.
§ 10Nonlinear equations after frequency localization
The linear \(L^p\) reconstruction is now available. What remains is to estimate the products generated by the equation. Two examples illustrate this: the cubic Klein–Gordon equation and the incompressible Navier–Stokes equations.
Writing the cubic term on the left, consider
This is §2 with \(N(u)=-\lambda u^3\); moving the term across the equality changes its sign. Applying \(P_k\) gives the exact equation
with data \(P_ku_0\) and \(P_ku_1\). Only the last term couples frequency bands.
For incompressible Navier–Stokes with viscosity normalized to one,
the localized system is
Here \(p\) denotes the pressure, not an exponent. The spatial multipliers commute with \(\partial_t\), \(\nabla\), and \(\Delta\); they do not commute with multiplication by \(v\).
The velocity at a large scale can transport a much finer feature, while two fine-scale oscillations can interact to produce a slowly varying component. The viscous term damps each band on its own, exactly as in §9; the transport term couples the bands. These different roles are visible in the localized system before any nonlinear estimate is attempted.
§ 11Products, Fourier support, and paraproducts
Multiplication adds frequency vectors. Recall \((f*g)(x)=\int_{\mathbb R^d}f(x-y)g(y)\,dy\). With our Fourier convention,
If \(\operatorname{supp}\widehat f\subset D_1\) and \(\operatorname{supp}\widehat g\subset D_2\) with \(D_1,D_2\) compact, then
Indeed, the integrand vanishes unless \(\eta\in D_1\) and \(\xi-\eta\in D_2\), which forces \(\xi\in D_1+D_2\), a compact hence closed set. This is a containment; cancellation can make the support smaller. More generally \(\operatorname{supp}(f*g)\subset\operatorname{supp}f+\operatorname{supp}g\) when the supports are compact; when the convolution exists and the supports are not compact, the containment uses the closure of the sum. Applied twice, it gives the claim of §2 that \(\widehat{u^3}\) is supported in \(\{|\xi|\le3R\}\) if \(\widehat u\) is supported in \(\{|\xi|\le R\}\).
For plane waves the rule is exact:
Frequency is a vector. Two large vectors can nearly cancel, leaving a small output frequency; their magnitudes alone do not determine the output. On the other hand, adding a small frequency set \(D_{\rm low}\) to a distant one \(D_{\rm high}\) only broadens \(D_{\rm high}\) slightly without moving it toward zero: high plus low stays near the high frequency.
An exact partition of the interactions. For \(f,g\in\mathcal S(\mathbb R^d)\),
The double series converges absolutely in \(L^2\): for Schwartz \(f\), \(\|P_{k'}f\|_\infty\le(2\pi)^{-d}\|\psi_{k'}\widehat f\|_1\) is \(O(2^{k'd})\) as \(k'\to-\infty\) and rapidly decreasing as \(k'\to\infty\), so \(\sum_{k',k''}\|P_{k'}f\|_\infty\|P_{k''}g\|_2<\infty\). Hence the terms may be regrouped freely. Fix the separation of ten dyadic indices and define the low-frequency cutoff relative to \(k'\) by
the second equality because \(\sum_{k''\le j}\psi(2^{-k''}\xi)=\varphi(2^{-j}\xi)\) for \(\xi\ne0\). Every pair \((k',k'')\) lies in exactly one of the three disjoint regions
Thus
定义 11.1Paraproduct pieces
For \(f,g\in\mathcal S(\mathbb R^d)\) and \(k\in\mathbb Z\), set
Since \(P_k\) is bounded on \(L^2\) and may be applied termwise,
The low–high term is obtained from the high–low term by interchanging \(f\) and \(g\): \(\Pi^{(k)}_{L\text{–}H}(f,g)=\Pi^{(k)}_{H\text{–}L}(g,f)\). The number ten is only a separation buffer. The strict inequality in the high–high range prevents pairs with \(|k'-k''|=10\) from being counted twice.
Where can the output frequency lie? In a high–low interaction, write \(j=k'\). The multiplier of \(\widetilde P_j=P_{\le j-10}\) is \(\varphi(2^{-(j-10)}\xi)\), supported in \(|\xi|\le2^{j-9}\). The supports therefore satisfy
and hence
The output remains comparable to \(2^j\). The support of \(\psi_k\) is \(\{2^{k-1}\le|\xi|\le2^{k+1}\}\); it misses this shell if \(2^{k+1}<(\frac12-2^{-9})2^j\), i.e. if \(k\le j-3\), and if \(2^{k-1}>(2+2^{-9})2^j\), i.e. if \(k\ge j+3\). So applying \(P_k\) to the \(j\)th high–low term gives zero unless \(|k-j|\le2\), and
The same statement holds with the roles reversed in a low–high interaction.
For high–high interactions, let \(J=\max(k',k'')\). Then \(|\xi_1|,|\xi_2|\le2^{J+1}\) and
but there is no positive lower bound. An output band must satisfy \(2^{k-1}\le2^{J+2}\), i.e. \(k\le J+3\); it may lie arbitrarily far below \(J\).
| Interaction | Output | Interpretation |
|---|---|---|
| High–low | Near the high input band, \(\lvert k-k'\rvert\le2\) | A slowly varying factor modulates a fine oscillation |
| Low–high | Near the high input band, \(\lvert k-k''\rvert\le2\) | The same mechanism with the factors reversed |
| High–high | Comparable or much lower frequencies, \(k\le J+3\) | Fine oscillations can reinforce or produce a slowly varying beat |
For example, in one dimension,
is a high–high interaction with low output. The real-valued identity
produces both a constant component and a higher harmonic. These examples explain why high–high interactions cannot be treated as though their output were always high.
The product estimates that motivate the decomposition concern quantities such as
The decomposition separates the three interaction patterns before estimating them. Cubic terms can be handled by applying the bilinear decomposition twice, or by sorting the three input frequencies in the expansion of \(P_k(u^3)\) from §2.
Remark. Scope of the formulas
The required estimates depend on the regularities and integrabilities of the factors; no unrestricted product of arbitrary distributions is asserted here. For Schwartz functions the formulas are justified directly, as above. In rough function spaces, convergence of the series must be established by the corresponding estimates.
§ 12Exercise: Khintchine's inequality
例 12.1Prove Lemma 7.3
Prove Khintchine's inequality for \(0<p<\infty\), and explain why the constants are independent of the number of terms. Hint: first take \(z_k=a_k\) real with \(\sum_ka_k^2=1\) and bound \(\mathbb E_\varepsilon e^{\lambda X}\), where \(X=\sum_k\varepsilon_ka_k\).
Solution
Real coefficients, upper bound. By homogeneity assume \(\sum_ka_k^2=1\). Comparing Taylor series, \((2n)!\ge2^nn!\) gives \(\cosh y\le e^{y^2/2}\). By independence, for \(\lambda>0\),
Chebyshev's inequality gives \(\mathbb P(X>t)\le e^{-\lambda t}\mathbb Ee^{\lambda X}\le e^{\lambda^2/2-\lambda t}\); choose \(\lambda=t\). Since \(X\) and \(-X\) have the same law,
The layer-cake formula then gives
Real coefficients, lower bound. The case \(p=2\) is the identity \(\mathbb EX^2=1\). If \(p\ge2\), Hölder on the probability space gives \((\mathbb E|X|^p)^{1/p}\ge(\mathbb EX^2)^{1/2}=1\). If \(0<p<2\), write \(2=\theta p+4(1-\theta)\) with \(\theta=2/(4-p)\in(0,1)\). Hölder with exponents \(1/\theta\) and \(1/(1-\theta)\) gives
so \(\mathbb E|X|^p\ge B_4^{-4(1-\theta)/\theta}>0\).
Complex coefficients. Write \(z_k=a_k+ib_k\) and \(X=X_1+iX_2\) with \(X_1=\sum\varepsilon_ka_k\), \(X_2=\sum\varepsilon_kb_k\). Since \(\max(|X_1|,|X_2|)\le|X|\le|X_1|+|X_2|\) and \(\sum|z_k|^2=\sum a_k^2+\sum b_k^2\), the real case applied to \(X_1\) and \(X_2\) gives both inequalities, with constants changed by factors depending only on \(p\) (for instance \(2^{-1/2}A_p\) below, from \(\mathbb E|X|^p\ge\max(\mathbb E|X_1|^p,\mathbb E|X_2|^p)\); and above \(\sqrt2B_p\) by Minkowski if \(p\ge1\), or \(2^{1/p}B_p\) from \(|X|^p\le|X_1|^p+|X_2|^p\) if \(p<1\)).
Independence of the number of terms. The only property of \((a_k)\) used was \(\sum_ka_k^2=1\): the moment generating bound \(e^{\lambda^2/2}\), hence the Gaussian tail and every moment bound, involve neither the length of the sequence nor the individual coefficients. This is what allows the inequality to be applied pointwise to \(z_k=P_kf(x)\) with \(F\) arbitrary in §7.
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